Axioms For Lattices And Boolean Algebras by R. Padmanabhan PDF

By R. Padmanabhan

The significance of equational axioms emerged first and foremost with the axiomatic method of Boolean algebras, teams, and jewelry, and later in lattices. This detailed learn monograph systematically offers minimum equational axiom-systems for numerous lattice-related algebras, whether they're given when it comes to subscribe to and meet or different varieties of operations resembling ternary operations. all of the axiom-systems is coded in a convenient means in order that you can actually persist with the typical connection one of the a number of axioms and to appreciate tips on how to mix them to shape new axiom platforms.

a brand new subject during this booklet is the characterization of Boolean algebras in the classification of all uniquely complemented lattices. the following, the distinguished challenge of E V Huntington is addressed, which -- in response to G Gratzer, a number one professional in smooth lattice thought -- is likely one of the difficulties that formed a century of study in lattice thought. between different issues, it truly is proven that there are infinitely many non-modular lattice identities that strength a uniquely complemented lattice to be Boolean, therefore offering a number of new axiom platforms for Boolean algebras in the category of all uniquely complemented lattices. eventually, a number of similar traces of analysis are sketched, within the type of appendices, together with one via Dr Willian McCune of the collage of recent Mexico, on functions of contemporary theorem-proving to the equational idea of lattices

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Example text

2. (D. Kelly and Padmanabhan [2002]) If p = q and p˜ = q˜ define a variety K relative to M, then the self-dual identity (5) s(x, y ∧ p, y ∨ q˜) = s˜(x, y ∨ p˜, y ∧ q) , where the variables x,y do not occur in p or q, defines K relative to L. Proof: If L ∈ K then (5) is readily verified. Conversely, suppose a lattice L satisfies (5), that is, (x∨((y∧p)∧(y∨˜ q )))∧((y∧p)∨(y∨˜ q )) = (x∧((y∨˜ p)∨(y∧q)))∨((y∨˜ p)∧(y∧q)) . Take x := o , y := u, cf. (2), where y1 , . . , yn are the variables of p and q.

1 is known as N5. 1 Modular Lattices within Lattices AxiomLattices 41 modular, because x < z but x ∨ (y ∧ z) = x ∨ o = x, while (x ∨ y) ∧ z = u ∧ z = z. Conversely, suppose there exist x, y, z such that x ≤ z but x ∨ (y ∧ z) = (x ∨ y) ∧ z. Since x ∨ (y ∧ x) = x = (x ∨ y) ∧ x, it follows that x = z, hence x < z. Since x ∨ (y ∧ z) ≤ (x ∨ y) ∧ z, it follows that x ∨ (y ∧ z) < (x ∨ y) ∧ z. Hence x ≤ y would imply y ∧ z < y ∧ z, a contradiction, while y ≤ x would imply the contradiction x < x ∧ z. Therefore x and y are incomparable.

16. (((x ∨ y) ∧ y) ∨ ((z ∧ y) ∨ (z ∧ y))) ∧ (u ∨ y) = y. Set X = z ∧y. Take u := z, v := y ∨((z ∨(X ∨X))∧((X ∨x)∨u)), w := u, in 11, then use 15 with x := X, w := u. 17. ((x ∧ y) ∨ (x ∧ y)) ∧ (z ∨ y) = (x ∧ y) ∨ (x ∧ y). Take x := x ∧ y, y := z, z := (x ∨ y) ∧ y, u := y in 15, then use 16 with z := x, u := (x ∧ y) ∨ (x ∧ y). 18. ((x ∨ y) ∧ y) ∨ ((x ∨ y) ∧ y) = y. Take x := x ∨ y in 17, then use 12 with z := x ∨ y, u := z. 19. (x ∧ y) ∧ (z ∨ y) = x ∧ y. Take y := x, z := y, u := x ∨ (x ∧ y), v := z in 8, then use 18 with y := x ∧ y, z := x.

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